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F.4 數學(trigonometry)

發問:

Find x when 0°≦x≦360°1. cos2x=0.4(ans:x=33.2°,146.8°,213.2° or 326.8°)2. 2tan3x= - 4(ans:x=38.9°,98.9°,158.9°,218,9°,278.9° or 338.9°)3. [(tan^2)x]-(開方3) tan x=0 (ans:x=0°,60,180°,240°or 360°)4. [(tan^2)x]-tanx- 2 = 0 (ans:x=63.4°,135°,243.4°or 315°) 5. [(cos^2)x]- [(sin^2)x] = - sinx (ans: x=90°,210° or... 顯示更多 Find x when 0°≦x≦360° 1. cos2x=0.4(ans:x=33.2°,146.8°,213.2° or 326.8°) 2. 2tan3x= - 4(ans:x=38.9°,98.9°,158.9°,218,9°,278.9° or 338.9°) 3. [(tan^2)x]-(開方3) tan x=0 (ans:x=0°,60,180°,240°or 360°) 4. [(tan^2)x]-tanx- 2 = 0 (ans:x=63.4°,135°,243.4°or 315°) 5. [(cos^2)x]- [(sin^2)x] = - sinx (ans: x=90°,210° or 330°) 6. (開方3)tan x= 2sinx (ans:x=0°,30,180°,330°or 360°) I want steps, thanks!

 

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最佳解答:

Corresponding steps as follows: 1) 2x = 66.4 or 360 - 66.4 or 360 + 66.4 or 720 - 66.4 2x = 66.4 or 293.6 or 426.4 or 653.6 2) tan 3x = -2 3x = 116.7 or 180 + 116.7 or 360 + 116.7 or 540 + 116.7 or 720 + 116.7 or 900 + 116.7 3) tan x ( tan x - Root 3 ) = 0 x = 0, 180, 360 or 60, 240 4) ( tan x - 2 )( tan x + 1 ) = 0 tan x = 2 or -1 x = 63.4 or 180 + 63.4 or 180 - 45 or 360 - 45 x = 63.4 or 243.4 or 135 or 315 5) ( 1 - sin^2 x ) - sin^2 x = -sin x 2 sin^2 x - sin x - 1 = 0 ( 2 sin x + 1 )( sin x - 1 ) = 0 sin x = 1 or -0.5 x = 90 or 180 + 30 or 360 - 30 x = 90 or 210 or 330 6) Root 3 ( sin x / cos x ) = 2 sin x ( Root 3 ) sin x = 2 sin x cos x sin x [ ( Root 3 ) - 2 cos x ] = 0 sin x = 0 or cos x = Root 3 / 2 x = 0 or 180 or 360 or 30 or 360 - 30 x = 0 or 180 or 360 or 30 or 3 30 Hope I can help you.

其他解答:8758B59A7FA1EEA7
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